Local variables go out of scope upon return, so you can’t return a pointer to a local variable.

You need to allocate it dynamically (on the heap), using malloc or new. Example:

int *create_array(void) {
    int *array = malloc(3 * sizeof(int));
    assert(array != NULL);
    array[0] = 4;
    array[1] = 65;
    array[2] = 23;
    return array;
 }
 void destroy_array(int *array) {
     free(array);
 }
 int main(int argc, char **argv) {
     int *array = create_array();
     for (size_t i = 0; i < 3; ++i)
         printf("%d\n", array[i]);
     destroy_array(array);
     return 0;
 }

Alternatively, you can declare the array as static, keeping in mind the semantics are different. Example:

int *get_array(void) {
    static int array[] = { 4, 65, 23 };
    return array;
 }
 int main(int argc, char **argv) {
     int *array = get_array();
     for (size_t i = 0; i < 3; ++i)
         printf("%d\n", array[i]);
     return 0;
 }

If you don’t know what static means, read this question & answer.