Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
[ad_1]
int main()
{
int a = 2147483647;
int c = a + a + 2;
printf("2a + 2 = %d, !(2a + 2) = %d, !c = %d\n", (2 * a + 2), !(a + a + 2), !c);
}
I got this when I run those codes above
2a + 2 = 0, !(2a + 2) = 0, !c = 1
a is Tmax which in binary form is 0111…111, so a + a + 2 is suposed to be 0000…0000.
I don’t understand why !(2a + 2) is not equal to 1 when (2a + 2) is actually 0, but !c is 1!!!
Please help me
[ad_2]